In \(\bigtriangleup\)XYZ, XY = 3cm, XZ = 5cm and YZ = 7cm. If the bisector of XYZ meets XZ at W, what is the length of XW?
-
1.5cm
- 2.5cm
- 3cm
- 4cm
- None of the above
The correct answer is: A
Explanation
Let XW = a, a :7
\(\frac{a}{5 - a}\) = \(\frac{3}{7}\)
7a = 15 - 3a
10a = 15
a = \(\frac{15}{10}\)
= \(\frac{3}{2}\)
= 1.5cm