What is the size of an exterior angle of a regular pentagon?

Explanation

Pentagon is a polygon with 5 sides. Sum of interior angles of polygon (regular) = (2n - 4) x 90o

= 5

= (10 - 4) x 90o

= 540o

each interior angle = \(\frac{540}{5}\)

= 108o

= 180o let x represent ext. angle

x + 108o = 180v

x = 180o - 108o

= 72o