Simplify without using tables \(\frac{log_26}{log_28}\) – \(\frac{log_23}{2log_2\frac{1}{2}}\)
-
\(\frac{1}{5}\)
- \(\frac{1}{2}\)
- \(\frac{-1}{2}\)
- \(\frac{log_23}{log_27}\)
The correct answer is: A
Explanation
log\(_2\)6 - log\(_2\)3 = log\(_2\) (\(\frac{6}{3}\))
= log\(_2\)2... A
log\(_2\)8 - 2log\(_2\)\(\frac{1}{2}\)
log\(_2\)8 - log\(_2\)\(\frac{1}{2}\)\(^2\)
log\(_2\)8 - log\(_2\)\(\frac{1}{4}\)
= log\(_2\) 32... B
\(\frac{A}{B}\) = \(\frac{log_22}{log_232}\)
N.B. log\(_2\)2 = 1
= \(\frac{1}{5}\)