Make y the subject of the formula Z = x\(^2\) + \(\frac{1}{y^3}\)
- y = \(\frac{1}{(Z - x^2)^3}\)
- y = \(\frac{1}{(Z + x^2)^{\frac{1}{3}}}\)
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y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)
- y = \(\frac{1}{\sqrt[3]{Z} - \sqrt[3]{x^2}}\)
The correct answer is: C
Explanation
Z = x\(^2\) + \(\frac{1}{y^3}\)
Z - x\(^2\) = \(\frac{1}{y^3}\)
y\(^3\) = \(\frac{1}{Z - x^2}\)
y = \(\sqrt[3]{\frac{1}{Z - x^2}}\)
∴ y = \(\frac{1}{\sqrt[3]{Z - x^2}}\)
y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)