Find the eleventh term of the progression 4, 8, 16…..

Explanation

a = 4, r = \(\frac{4}{2}\)

\(\frac{8}{4}\) = 2

n = 11

T_n = ar^{n - 1}

T₁₁ = 4(2)^{11 - 1}

4(2)¹⁰ = 2¹²

since 4 = 2²

= 2¹²