\(\begin{array}{c|c} Scores(x) & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency(f) & 7 & 11 & 6 & 7 & 7 & 5 & 3\end{array}\)
In the distribution above, the mode and median respectively are
- 1,3
-
1, 2
- 3, 3
- 0, 2
The correct answer is: B
Explanation
From the distribution, Mode = 1 and
Median = \(\frac{2 + 2}{2}\)
= 2
= 1, 2