Four interior angles of a pentagon are 90o – xo, 90o + xo, 110o -…

Explanation

Let the fifth interior angle be y: sum of interior angle of a pentagon

= (2 x 5 - 4) x 90^o

= 6 x 90^o

= 540^o

(90 - x) + (90 + x) + (110 - 2x) + (110 + 2x) + y = 540^o

400^o + y = 540^o

y = 540 - 400^o

y = 140^o