If \(log_{10} 2 = 0.3010\) and \(log_{10} 3 = 0.4771\), evaluate; without using logarithm tables, \(log_{10} 4.5\)
- 0.3010
- 0.4771
-
0.6532
- 0.9542
The correct answer is: C
Explanation
If \(log_{10} 2 = 0.3010\) and \(log_{10} 3 = 0.4771\),
\(\log_{10} 4.5 = \log_{10} (\frac{3 \times 3}{2})\)
\(log_{10} 3 + log_{10} 3 - log_{10} 2 = 0.4771 + 0.4771 - 0.3010\)
= 0.6532