Given that 3x – 5y – 3 = 0, 2y – 6x + 5 = 0 the value of (x, y) is
- (\(\frac{-1}{8}, \frac{19}{24}\))
- 8, \(\frac{24}{19}\)
- -8, \(\frac{24}{19}\)
-
(\(\frac{19}{24}, \frac{-1}{8}\))
The correct answer is: D
Explanation
3x - 5y = 3, 2y - 6x = -5-5y + 3x = 3........{i} x 2
2y - 6x = -5.........{ii} x 5
Substituting for x in equation (i)
-5y + 3(\(\frac{19}{24}\)) = 3
-5y + 3 x \(\frac{19}{24}\) = 3
-5y = \(\frac{3 - 19}{8}\)
-5 = \(\frac{24 - 19}{8}\)
= \(\frac{5}{8}\)
y = \(\frac{5}{8 \times 5}\)
y = \(\frac{-1}{8}\)
(x, y) = (\(\frac{19}{24}, \frac{-1}{8}\)