The solution of the quadratic equation px2 + qx + b = 0 is
- \(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
- \(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
-
\(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
- \(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)
The correct answer is: C
Explanation
px2 + qx + b = 0Using almighty formula
\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)
Where a = p, b = q and c = b
substitute for this value in equation (i)
= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)