What are K and L respectively if \(\frac{1}{2}\)(3y – 4x)2 = (8x2 + kxy + Ly2)
-
-12, \(\frac{9}{2}\)
- -6, 9
- 6, 9
- 12, \(\frac{9}{2}\)
The correct answer is: A
Explanation
\(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)\(\frac{1}{2}\)(9y2 - 24xy + 16x2) = 8x2 + kxy + Ly2
\(\frac{9}{2}\)y2 - 12xy) = kxy + Ly2
k = -12 ∴ L = \(\frac{9}{2}\)