OXYZW is a pyramid with a square base such that OX = OY= OZ = OW = 5cm and XY = XW = YZ = WZ = 6cm. Find the height OT
- 2\(\sqrt{5}\)
- 3
- 4
-
4\(\sqrt{3}\)
The correct answer is: D
Explanation
xz2 = 62 + 6236 + 36 = 72
xz = \(\sqrt{72}\)
6\(\sqrt{2}\) = xT
\(\frac{6\sqrt{2}}{2}\) = \(\frac{3}{\sqrt{2}}\)
OT2 = 52 + (3\(\sqrt{2}\))2 = 25 + 18
OT = 4\(\sqrt{3}\)