MN is tangent to the given circle at M, MR, and MQ are two chords. IF QMN is 60º and MNQ is 40º. Find RMQ
- 120o
- 110o
- 60o
-
20o
The correct answer is: D
Explanation
QMN = 60º
MRQ = 60º(angle in the alternate segment are equal)
MQN = 80º(angle sum of a \(\bigtriangleup\) = 180º)
60 + x = 80º(exterior angle = sum of opposite interior angles)
x = 80º - 60º = 20º
RMQ = 20º