\(\begin{array}{c|c} \text{Class Interval} & 1 – 5 & 6 – 10 & 11 – 15 & 16 – 20 & 21 – 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array}\)
Estimate the median of the frequency distribution above
- 10\(\frac{1}{2}\)
- 11\(\frac{1}{2}\)
-
12
- 13
The correct answer is: C
Explanation
Median = L + [\(\frac{\frac{N}{2} - f}{fm}\)]hN = Sum of frequencies
L = lower class boundary of median class
f = sum of all frequencies below L
fm = frequency of modal class and
h = class width of median class
Median = 11 + [\(\frac{\frac{50}{2} - 21}{20}\)]5
= 11 + (\(\frac{25 - 21}{20}\))5
= 11 + (\(\frac{(4)}{20}\))
11 + 1 = 12