In the diagram, O is the centre of the circle. If SOQ is a diameter…

Explanation

< SRP = < SQP = 38^o (angle in the same segment of a circle are equal)

But < SPQ = 90^o (angle in a semicircle)

also < PSQ + < SQP + < SPQ = 180^o (angles in a triangle = 180^o)

< PSQ + 38^o + 90^o = 190^o

< PSQ = 128^o = 180^o

PSQ = 180^o - 128^o

PSQ = 52^o