Evaluate \(\frac{(81)^{\frac{3}{4}} – (27)^{\frac{1}{3}}}{3 \times 2^3}\)
- 27
-
1
- \(\frac{1}{3}\)
- \(\frac{1}{8}\)
The correct answer is: B
Explanation
\(\frac{(81)^{\frac{3}{4}} - (27)^{\frac{1}{3}}}{3 \times 2^3}\)
= \(\frac{(3^{4})^{\frac{3}{4}} - (3^{3})^{\frac{1}{3}}}{3 \times 2^{3}}\)
= \(\frac{3^{3} - 3^{1}}{24}\)
= \(\frac{27 - 3}{24} = 1\)