Find the value of k if \(\frac{5 + 2r}{(r + 1)(r – 2)}\) expressed in partial fraction is \(\frac{k}{r – 2}\) + \(\frac{L}{r + 1}\) where K and L are constants
-
3
- 2
- 1
- -1
The correct answer is: A
Explanation
5 + 2r = k(r + 1) + L(r - 2)but r - 2 = 0 and r = 2
9 = 3k
k = 3