Two binary operations \(\ast\) and \(\oplus\) are defines as m \(\ast\) n = mn – n – 1 and m \(\oplus\) n = mn + n – 2 for all real numbers m, n.
Find the value of 3 \(\oplus\) (4 \(\ast\) 5)
- 60
- 57
-
54
- 42
The correct answer is: C
Explanation
m \(\ast\) n = mn - n - 1, m \(\oplus\) n = mn + n - 2
3 \(\oplus\) (4 \(\ast\) 5) = 3 \(\oplus\) (4 x 5 - 5 - 1) = 3 \(\oplus\) 14
3 \(\oplus\) 14 = 3 x 14 + 14 - 2
= 54