In a basket of fruits, there are 6 grapes, 11 bananas and 13 oranges, if one fruit is chosen at random, what is the probability that the fruit is either a grape or a banana?
-
\(\frac{17}{30}\)
- \(\frac{11}{30}\)
- \(\frac{6}{30}\)
- \(\frac{5}{30}\)
The correct answer is: A
Explanation
Pgrape or Pbanana = \(\frac{6}{30}\) + \(\frac{11}{30}\)= \(\frac{17}{30}\)