If \(1011_2\) + \(X_7\) = \(25_{10}\), solve for X.

Explanation

\(1011_2 + X_7 = 25_{10} = 1011_2 = 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0\)

= 8 + 0 + 2 + 1

= \(11_{10}\)

\(X_7 = 25_{10} - 11_{10}\)

= \(14_{10}\)

\(\begin{array}{c|c}
7 & 14 \\ 7 & 2 R 0 \\ & 0 R 2
\end{array}\)

X = \(20_7\)