Evaluate [\(\frac{1}{0.03}\) \(\div\) \(\frac{1}{0.024}\)]-1 correct to 2 decimal places

Explanation

[\(\frac{1}{0.03}\) + \(\frac{1}{0.024}\)]

= [\(\frac{1}{0.03 \times 0.024}\)]^-1

= [\(\frac{0.024}{0.003}\)]^-1

= \(\frac{0.03}{0.024}\)

= \(\frac{30}{24}\) = 1.25