If y = 243(4x + 5)-2, find \(\frac{dy}{dx}\) when x = 1
The correct answer is: A
Explanation
y = 243(4x + 5)-2, find \(\frac{dy}{dx}\)= -1944(4x + 5)-3
= 1944(9)-3
\(\frac{dy}{dx}\) when x = 1
= -\(\frac{1944}{9^3}\)
= -\(\frac{1944}{729}\)
= \(\frac{-8}{3}\)