For what value of x does 6 sin (2x – 25)o attain its maximum value in the range 0o \(\leq\) x \(\leq\) 180o
- 12\(\frac{1}{2}\)
- 32\(\frac{1}{2}\)
-
57\(\frac{1}{2}\)
- 147\(\frac{1}{2}\)
The correct answer is: C
Explanation
y = 6 sin (2x - 25)o\(\frac{dy}{dx}\) = -12 cos(2x - 25o)
\(\frac{dy}{dx}\) = 0
-12 cos x (2x - 25o) = 0
= cos(2x - 25o) = 0
= 2x - 25o = cos-1(0)
= 2x - 25o
= 90o
x = \(\frac{115}{2}\)