A chord of a circle radius \(\sqrt{3cm}\) subtends an angle of 60° on the circumference of he circle. Find the length of the chord
- \(\frac{\sqrt{3}}{2}\)
- \(\frac{3}{2}\)
- 3
-
\(\sqrt{3}\)cm
The correct answer is: D
Explanation
Length of chord = \(2r \times \sin(\frac{\theta}{2})\)
= \( 2 \times \sqrt{3} \times \sin(\frac{60}{2})\)
= \(2 \times \sqrt{3} \times \frac{1}{2}\)
= \(\sqrt{3}\) cm.