From a point P, the bearings of two points Q and R are N670W and N230E respectively. If the bearing of R from Q is N680E and PQ = 150m, calculate PR
- 120m
- 140m
-
150m
- 160m
The correct answer is: C
Explanation
\(\frac{150}{PR}\) = tan45º
PR = \(\frac{150}{tan45º}\) = 150m