What is the derivative of t2 sin (3t – 5) with respect to t?
- 6t cos (3t - 5)
- 2t sin (3t - 5) - 3t2 cos (3t - 5)
-
2t sin (3t - 5) + 3t2 cos (3t - 5)
- 2t sin (3t - 5) + t2 cos 3t
The correct answer is: C
Explanation
t2 sin (3t - 5) = 2t sin ( 3t - 5) + t2 x 3 cos (3t - 5) = 2t sin (3t - 5) + 3t2 cos (3t - 5).Detailed answer below was provided by Ifechuks, a female prospective student of Okopoly.