If the diagram is the graph of y = x\(^2\), the shaded area is
- 64 square units
-
\(\frac{128}{3}\) square units
- 32 square units
- \(\frac{64}{3}\) square units
The correct answer is: B
Explanation
A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\)16 - x\(^2\)dx = [16 - \(\frac{x^3}{3} + c]^{4}_{0}\)
= \(\frac{128}{3}\) square units
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