The sixth term of an A.P is half of its twelfth term. The first term of the A.P is equal to
- zero
- half of the common difference
- double the common difference
-
the common difference
The correct answer is: D
Explanation
1st statement: U6 = 1/2(U12)a + (n -1)d = 1/2[a + (n-1)d]
a + 5d = a + 11d
2(a + 5d) = a + 11d
2a + 10d = a + 11d
Solving, => a = d
Hence the first term is equal to the common difference
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