If dy/dx = 2x – 3 and y = 3 when x = 0, find y in terms of x.
- 2x2 - 3x
- x2 - 3x
- x2 - 3x - 3
-
x2 - 3x + 3
The correct answer is: D
Explanation
dy/dx = 2x - 3y = ∫2x - 3 dx => y = x2 - 3x + c
3 = (0)2 - 3(0) + c
=> c = 3
Thus y = x2 - 3x + 3