If x varies directly as √n and x = 9 when n = 9, find x when n = (17/9)
- 4
- 27
- √3
-
√17
The correct answer is: D
Explanation
\(x \propto \sqrt{n}\)
\(x = k \sqrt{n}\)
\(9 = k \sqrt{9} \implies 9 = 3k\)
\(k = 3\)
\(x = 3 \sqrt{n}\)
When n = 17/9,
\(x = 3 \times \sqrt{\frac{17}{9}} = \sqrt{17}\)