The probability of a student passing any exam is 2/3. If the student takes three exams, what is the probability that he will not pass any of them?
- 2/3
- 4/9
- 8/27
-
1/27
The correct answer is: D
Explanation
P(not passing exam) = \(1 - \frac{2}{3} = \frac{1}{3}\)
P(not passing any of the three exams) = \(\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3}\)
= \(\frac{1}{27}\)