
Find the mean of the distribution above
The correct answer is: C
Explanation
\(Mean = \frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}\\=\frac{(0 + 2 + 4 + 3 + 36)}{15}\\=\frac{45}{15}=3\)
Find the mean of the distribution above
\(Mean = \frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}\\=\frac{(0 + 2 + 4 + 3 + 36)}{15}\\=\frac{45}{15}=3\)