In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40°. Find ∠PSQ
-
40o
- 30o
- 20o
- 10o
The correct answer is: A
Explanation
R = P (base ∠s of isc Δ, ps = RS)
∴R = 40°
∠PSQ = R (∠s in alternate segment)
∴∠PSQ = 40°