In the diagram PQR is a straight line and PS is a tangent to the circle < QRS with |PS| = |SR| and < SPR = 40°. Find PSQ
- 20o
-
40o
- 10o
- 30o
The correct answer is: B
Explanation
PS = SR
\(\bigtriangleup\)PSR is an isosceles
< P = < SPQ = 40°
< R = < SRQ
< PSQ = < SRQ (alternate segment)
< PSQ = 40°