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If sin θ = -1/2 for 0 < θ < 360o, the value of θ...

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Mathematics JAMB 2005

If sin θ = –1/2 for 0 < θ < 360o, the value of θ is

  • 30o and 150o
  • 150o and 210o
  • 210o and 330o checkmark
  • 150o and 330o

The correct answer is: C

Explanation

sin θ = -1/2
= -0.5
θ = sin-1 (0.5)
θ = 30o
Since θ is negative
θ = 180 + 30 = 210o
θ = 360 - 30 = 330o
∴θ = 210o and 330o
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