Evaluate \(\int_{-4}^0(1 – 2x)dx\)
- -16
- -20
-
20
- 10
The correct answer is: C
Explanation
\(\int_{-4}^0(1 - 2x)dx=[x-x^2]_{-4}^0\\= (0 - 0 + C) - (-4 - (-4)^2 + C)\\
= C - (-4-16+C)\\
= C-(-20+C)\\
= C+20-C\\
= 20\)