If (K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\), what is the value of k?

Explanation

(K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\)

(K*6\(^1\) + 2*6\(^0\)) 3*6\(^0\) = 3*5\(^0\)(K*5\(^1\) + 4*5\(^0\))

3(6K + 2) = 3(5K + 4)

6K + 2 = 5K + 4

6K - 5K = 4 - 2

K = 2