
In the diagram above, POQ is a diameter of the circle PQRS. If ∠PSR = 145°, find x°
The correct answer is: A
Explanation

∠PSQ = 90° (∠ in semi circle)
∠PSQ + ∠QSR = 145°
90 + ∠QSR = 145
∠QSR = 145 - 90
∠QSR = 55°
BUt x° = ∠QSR (∠s in the same segment)
∴x° = 55°