Solve the inequalities for which \(\frac{x+4}{3}-\frac{x-3}{2} < 4\)
- x < 7
-
x > -7
- x < -7
- x > 7
The correct answer is: B
Explanation
\(\frac{x+4}{3}-\frac{x-3}{2} < 4\\
\frac{(2(x+4))-(3(x-3))}{6}<4\)
2(x+4) – 3(x-3) < 4 x 6
2x + 8 – 3x+9 < 24
-x + 17 < 24
-x < 24 – 17
-x < 7
x > -7