If \(T = 2\pi \sqrt{\frac{l}{g}}\), make g the subject of the formula
- (4ฯ l2) / T
-
(4ฯ2l) / T2
- (4ฯ2l2) / T2
- (2ฯโl) / T
The correct answer is: B
Explanation
\(T = 2\pi \sqrt{\frac{l}{g}}\)
\(\frac{T}{2\pi} = \sqrt{\frac{l}{g}}\)
\((\frac{T}{2\pi})^{2} = \frac{l}{g}\)
\(\therefore g = \frac{4 \pi^{2} l}{T^{2}}\)