The solution of the quadratic inequality (x\(^2\) + x – 12) ≥ 0 is
- x ≥ -3 or x ≤ 4
- x ≥ 3 or x ≥ -4
- x ≤ 3 or x \(\leq\) -4
-
x ≥ 3 or x ≤ -4
The correct answer is: D
Explanation
(x\(^2\) + x - 12) ≥ 0
(x + 4)(x - 3) ≥ 0
Either x + 4 ≥ 0 implies x ≥ - 4
Or x - 3 ≥ 0 implies x ≥ 3
∴ x ≥ 3 or x \(\leq\) -4
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