Find the value of x for which 2(32x-1) = 162

Find the value of x for which 2(3^2x-1) = 162

The correct answer is: A

2(3^2x-1) = 162
3^2x-1 = 162/2
3^2x-1 = 81
3^2x-1 = 3²
2x - 1 = 4 (equating the indices)
2x = 5
⁵/₂
x =