If the lines 3y = 4x – 1 and qy = x + 3 are parallel to each other, the value of q is
The correct answer is: D
Explanation
If the line 3y = 4x – 1 is parallel t[ line qy = x + 3Implies gradient of 3y = 4x – 1
Y = 4/3x - 1/3
∴Gradient = 4/3
Gradient of line qy = x + 3
Y = 1/qx + 3/q
∴ Gradient = 1/q
4/3 = 1/q
4q = 3
Q = 3/4