If p varies inversely as the square of q and p=8 when q=4, find q when p =32
- \(\pm\)16
- \(\pm\)8
- \(\pm\)4
-
\(\pm\)2
The correct answer is: D
Explanation
p ∝ 1/q
p = k/q
K = q\(^2\)p
= 4\(^2\)(8)
∴p = 128/q
32 = 128/q
q\(^2\) = 128/32
q\(^2\) = 4
q = √4 = \(\pm\) 2
There is an explanation video available .