Solve the quadratic inequalities x\(^2\) – 5x + 6 ≥ 0
- x ≤ 2, x ≥ 3
-
x ≤ 3, x ≥ 2
- x ≤ -2, x ≥ -3
- x ≤-3, x ≥ 2
The correct answer is: B
Explanation
x\(^2\) - 5x + 6 = 0
(X-2)(X-3) = 0
X-2 = 0 implies X = 2
X-3 = 0 implies X = 3
∴ x ≤ 3, x ≥ 2
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