The locus of a point equidistant from two points p(6,2) and R(4,2) is a perpendicular bisector of PR passing through?
- (2,5)
-
(5,2)
- (1,0)
- (0,1)
The correct answer is: B
Explanation
\(X = \frac{6+4}{2}=\frac{10}{2}=5\\
Y = \frac{2+2}{2}=\frac{4}{2}=2\\
∴X,Y = (5,2)\)
There is an explanation video available .