What is the mean of the data t, 2t-1, t-2, 2t -1, 4t and 2t+2?

Explanation

\(Mean = \frac{t+2t-1+t-2+2t-1+4t+2t+2}{6}\\
Mean = \frac{12t-2}{6}\\
=\frac{2(6t-1)}{6}\\
=\frac{6t-1}{3}\\
=\frac{6t}{3}- \frac{1}{3}\\
=2t-\frac{1}{3}\)

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