Find the range of values of x for which 3x – 7 \(\leq\) 0 and x + 5 > 0?
- -5 < x < \(\frac{7}{3}\)
- -5 \(\leq\) x \(\leq\) \(\frac{7}{3}\)
-
-5 < x \(\leq\) \(\frac{7}{3}\)
- -5 \(\leq\) x < \(\frac{7}{3}\)
The correct answer is: C
Explanation
3x - 7 \(\leq\) 0 and x + 5 > 0
3x \(\leq\) 7 and x > -5
x \(\leq\) \(\frac{7}{3}\)
∴ Range -5 < x \(\leq\) \(\frac{7}{3}\)
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