Find to infinity, the sum of the sequence \(1, \frac{9}{10}, \left(\frac{9}{10}\right)^2, \left(\frac{9}{10}\right)^3,…..\)
-
10
- 9
- 10/9
- 9/10
The correct answer is: A
Explanation
a = 1, r =\(\frac{9}{10}\)
S\(_n\) = \(\frac{a}{1 - r}\)
S\(_n\) = \(\frac{1}{1-\frac{9}{10}}\)
= 1\(\div \frac{1}{10}\)
=1\(\times \frac{10}{1}\) = 10