Factorize completely \(\frac{x^{3} + 3x^{2} – 10x}{2x^{2} – 8}\)
- x(x-5)2(x+2)
- x(x-5)2(x-2)
-
x(x+5)2(x+2)
- x2+52x+4
The correct answer is: C
Explanation
\(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8} = \frac{x(x^{2} + 3x - 10)}{2(x^{2} - 4)}\)
= \(\frac{x(x^{2} - 2x + 5x - 10)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x - 2)(x + 5)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x + 5)}{2(x + 2)}\)
There is an explanation video available .